science_blog_fun

How much water would it take to drown Mt. Everest?

Let us wildly oversimplify the Earth as a perfect sphere, pretend all land is exactly at sea level, and then pour on the water until Mount Everest’s summit (8 848 m) disappears under a global bathtub.^[1]


1. The rough‑and‑ready math

  1. Earth’s surface area
    $A = 4\pi R^2$, with $R ≈ 6\,371\text{ km}$.
    $ A \;\approx\; 4\pi (6\,371)^2 \;\approx\; 510\times10^6\;\text{km}^2 $

  2. Desired flood depth
    $H = 8.848\text{ km}$ (Everest above “sea” level).

  3. Volume of water

V = A × H ≈ (510 × 10^6 km²) × (8.848 km) ≈ 4.5 × 10^9 km³

That’s 4.5 billion cubic kilometers of water.


2. Putting it in perspective


3. What does that look like?


┌─────────────────────────────────────────────┐
│                                             │
│      🌊 Ever-Deepening Global Bathtub       │
│                                             │
│      ┏━━━━━━━━━━━━━━━━━━━━━━━━━━━━━┓        │
│      ┃ 8 848 m — Everest summit 🏔 ┃        │
│      ┗━━━━━━━━━━━━━━━━━━━━━━━━━━━━━┛        │
│      \~4.5×10^9 km³ total water added       │
│                                             │
└─────────────────────────────────────────────┘


4. The fine print (aka “real‑world gets messy”)


Answer: You’d need on the order of 4.5 billion km³ of extra water – roughly three times the volume of all water currently on Earth – to submerge Mount Everest under a perfectly flat global sea.


This assumes no existing ocean depth and ignores every other geographic complication.